50x-0.01x^2=0

Solution for 50x-0.01x^2=0 equation:

50x-0.01x^2=0

a = -0.01; b = 50; c = 0;
Δ = b2-4ac
Δ = 502-4·(-0.01)·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-50}{2*-0.01}=\frac{-100}{-0.02}
=+5000
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+50}{2*-0.01}=\frac{0}{-0.02}
=0
$